(3x+2)=(4x-9)+80

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Solution for (3x+2)=(4x-9)+80 equation: 



(3x+2)=(4x-9)+80

We move all terms to the left:

(3x+2)-((4x-9)+80)=0

We get rid of parentheses

3x-((4x-9)+80)+2=0



We calculate terms in parentheses: -((4x-9)+80), so:

(4x-9)+80

We get rid of parentheses

4x-9+80

We add all the numbers together, and all the variables

4x+71

Back to the equation:

-(4x+71)



We get rid of parentheses

3x-4x-71+2=0

We add all the numbers together, and all the variables

-1x-69=0

We move all terms containing x to the left, all other terms to the right

-x=69

x=69/-1

x=-69

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