(3x+2)+2=(22-x)=2

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Solution for (3x+2)+2=(22-x)=2 equation: 



(3x+2)+2=(22-x)=2

We move all terms to the left:

(3x+2)+2-((22-x))=0

We add all the numbers together, and all the variables

(3x+2)-((-1x+22))+2=0

We get rid of parentheses

3x-((-1x+22))+2+2=0



We calculate terms in parentheses: -((-1x+22)), so:

(-1x+22)

We get rid of parentheses

-1x+22

Back to the equation:

-(-1x+22)



We add all the numbers together, and all the variables

3x-(-1x+22)+4=0

We get rid of parentheses

3x+1x-22+4=0

We add all the numbers together, and all the variables

4x-18=0

We move all terms containing x to the left, all other terms to the right

4x=18

x=18/4

x=4+1/2

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