-x-2(x+1)=5(x+2)

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Solution for -x-2(x+1)=5(x+2) equation: 



-x-2(x+1)=5(x+2)

We move all terms to the left:

-x-2(x+1)-(5(x+2))=0

We add all the numbers together, and all the variables

-1x-2(x+1)-(5(x+2))=0

We multiply parentheses

-1x-2x-(5(x+2))-2=0



We calculate terms in parentheses: -(5(x+2)), so:

5(x+2)

We multiply parentheses

5x+10

Back to the equation:

-(5x+10)



We add all the numbers together, and all the variables

-3x-(5x+10)-2=0

We get rid of parentheses

-3x-5x-10-2=0

We add all the numbers together, and all the variables

-8x-12=0

We move all terms containing x to the left, all other terms to the right

-8x=12

x=12/-8

x=-1+1/2

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