5(y-2)-2=2(y+)-5

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Solution for 5(y-2)-2=2(y+)-5 equation: 



5(y-2)-2=2(y+)-5

We move all terms to the left:

5(y-2)-2-(2(y+)-5)=0

We add all the numbers together, and all the variables

5(y-2)-(2(+y)-5)-2=0

We multiply parentheses

5y-(2(+y)-5)-10-2=0



We calculate terms in parentheses: -(2(+y)-5), so:

2(+y)-5

We multiply parentheses

2y-5

Back to the equation:

-(2y-5)



We add all the numbers together, and all the variables

5y-(2y-5)-12=0

We get rid of parentheses

5y-2y+5-12=0

We add all the numbers together, and all the variables

3y-7=0

We move all terms containing y to the left, all other terms to the right

3y=7

y=7/3

y=2+1/3

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