(3x+2)(x-2)=(x+6)(3x-8)

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Solution for (3x+2)(x-2)=(x+6)(3x-8) equation: 



(3x+2)(x-2)=(x+6)(3x-8)

We move all terms to the left:

(3x+2)(x-2)-((x+6)(3x-8))=0

We multiply parentheses ..

(+3x^2-6x+2x-4)-((x+6)(3x-8))=0



We calculate terms in parentheses: -((x+6)(3x-8)), so:

(x+6)(3x-8)

We multiply parentheses ..

(+3x^2-8x+18x-48)

We get rid of parentheses

3x^2-8x+18x-48

We add all the numbers together, and all the variables

3x^2+10x-48

Back to the equation:

-(3x^2+10x-48)



We get rid of parentheses

3x^2-3x^2-6x+2x-10x-4+48=0

We add all the numbers together, and all the variables

-14x+44=0

We move all terms containing x to the left, all other terms to the right

-14x=-44

x=-44/-14

x=3+1/7

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