12=(4+w)w

Solution for 12=(4+w)w equation:

12=(4+w)w

We move all terms to the left:

12-((4+w)w)=0

We add all the numbers together, and all the variables

-((w+4)w)+12=0


We calculate terms in parentheses: -((w+4)w), so:

(w+4)w

We multiply parentheses

w^2+4w

Back to the equation:

-(w^2+4w)


We get rid of parentheses

-w^2-4w+12=0

We add all the numbers together, and all the variables

-1w^2-4w+12=0

a = -1; b = -4; c = +12;
Δ = b2-4ac
Δ = -42-4·(-1)·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8}{2*-1}=\frac{-4}{-2}
=+2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8}{2*-1}=\frac{12}{-2}
=-6
$