4y+3(y-1)=2(3y-4)

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Solution for 4y+3(y-1)=2(3y-4) equation: 



4y+3(y-1)=2(3y-4)

We move all terms to the left:

4y+3(y-1)-(2(3y-4))=0

We multiply parentheses

4y+3y-(2(3y-4))-3=0



We calculate terms in parentheses: -(2(3y-4)), so:

2(3y-4)

We multiply parentheses

6y-8

Back to the equation:

-(6y-8)



We add all the numbers together, and all the variables

7y-(6y-8)-3=0

We get rid of parentheses

7y-6y+8-3=0

We add all the numbers together, and all the variables

y+5=0

We move all terms containing y to the left, all other terms to the right

y=-5

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