(3x+12)=(4x-15)=0

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Solution for (3x+12)=(4x-15)=0 equation: 



(3x+12)=(4x-15)=0

We move all terms to the left:

(3x+12)-((4x-15))=0

We get rid of parentheses

3x-((4x-15))+12=0



We calculate terms in parentheses: -((4x-15)), so:

(4x-15)

We get rid of parentheses

4x-15

Back to the equation:

-(4x-15)



We get rid of parentheses

3x-4x+15+12=0

We add all the numbers together, and all the variables

-1x+27=0

We move all terms containing x to the left, all other terms to the right

-x=-27

x=-27/-1

x=+27

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