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(3x+12)(-2x+10)=0
We multiply parentheses ..
(-6x^2+30x-24x+120)=0
We get rid of parentheses
-6x^2+30x-24x+120=0
We add all the numbers together, and all the variables
-6x^2+6x+120=0
a = -6; b = 6; c = +120;
Δ = b2-4ac
Δ = 62-4·(-6)·120
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-54}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+54}{2*-6}=\frac{48}{-12} =-4 $
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