-2(x-3)=4(-x-2)

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Solution for -2(x-3)=4(-x-2) equation: 



-2(x-3)=4(-x-2)

We move all terms to the left:

-2(x-3)-(4(-x-2))=0

We add all the numbers together, and all the variables

-2(x-3)-(4(-1x-2))=0

We multiply parentheses

-2x-(4(-1x-2))+6=0



We calculate terms in parentheses: -(4(-1x-2)), so:

4(-1x-2)

We multiply parentheses

-4x-8

Back to the equation:

-(-4x-8)



We get rid of parentheses

-2x+4x+8+6=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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