x+8(12-x)=7x+3(2-x)

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Solution for x+8(12-x)=7x+3(2-x) equation: 



x+8(12-x)=7x+3(2-x)

We move all terms to the left:

x+8(12-x)-(7x+3(2-x))=0

We add all the numbers together, and all the variables

x+8(-1x+12)-(7x+3(-1x+2))=0

We multiply parentheses

x-8x-(7x+3(-1x+2))+96=0



We calculate terms in parentheses: -(7x+3(-1x+2)), so:

7x+3(-1x+2)

We multiply parentheses

7x-3x+6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-7x-(4x+6)+96=0

We get rid of parentheses

-7x-4x-6+96=0

We add all the numbers together, and all the variables

-11x+90=0

We move all terms containing x to the left, all other terms to the right

-11x=-90

x=-90/-11

x=8+2/11

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