(3x+1)/3=(6x+9)/7

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Solution for (3x+1)/3=(6x+9)/7 equation: 



(3x+1)/3=(6x+9)/7

We move all terms to the left:

(3x+1)/3-((6x+9)/7)=0

We calculate fractions


3x/()+(-((6x+9)*3)/()=0



We calculate terms in parentheses: +(-((6x+9)*3)/(), so:

-((6x+9)*3)/(

We multiply all the terms by the denominator


-((6x+9)*3)



We calculate terms in parentheses: -((6x+9)*3), so:

(6x+9)*3

We multiply parentheses

18x+27

Back to the equation:

-(18x+27)



We get rid of parentheses

-18x-27

Back to the equation:

+(-18x-27)



We get rid of parentheses

3x/()-18x-27=0

We multiply all the terms by the denominator


3x-18x*()-27*()=0

We add all the numbers together, and all the variables

3x-18x*()=0

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