1(y-7)=2(13+y)

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Solution for 1(y-7)=2(13+y) equation: 



1(y-7)=2(13+y)

We move all terms to the left:

1(y-7)-(2(13+y))=0

We add all the numbers together, and all the variables

1(y-7)-(2(y+13))=0



We calculate terms in parentheses: -(2(y+13)), so:

2(y+13)

We multiply parentheses

2y+26

Back to the equation:

-(2y+26)



We get rid of parentheses

1(y-7)-2y-26=0

We add all the numbers together, and all the variables

-2y+1(y-7)-26=0

We move all terms containing y to the left, all other terms to the right

-2y+1(y-7)=26

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