-(2(2-y)-(2y-3))-5y=4(y+3)

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Solution for -(2(2-y)-(2y-3))-5y=4(y+3) equation: 



-(2(2-y)-(2y-3))-5y=4(y+3)

We move all terms to the left:

-(2(2-y)-(2y-3))-5y-(4(y+3))=0

We add all the numbers together, and all the variables

-(2(-1y+2)-(2y-3))-5y-(4(y+3))=0

We add all the numbers together, and all the variables

-5y-(2(-1y+2)-(2y-3))-(4(y+3))=0



We calculate terms in parentheses: -(2(-1y+2)-(2y-3)), so:

2(-1y+2)-(2y-3)

We multiply parentheses

-2y-(2y-3)+4

We get rid of parentheses

-2y-2y+3+4

We add all the numbers together, and all the variables

-4y+7

Back to the equation:

-(-4y+7)





We calculate terms in parentheses: -(4(y+3)), so:

4(y+3)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We get rid of parentheses

-5y+4y-4y-7-12=0

We add all the numbers together, and all the variables

-5y-19=0

We move all terms containing y to the left, all other terms to the right

-5y=19

y=19/-5

y=-3+4/5

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