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(3x)/(5-2x)=x
We move all terms to the left:
(3x)/(5-2x)-(x)=0
Domain of the equation: (5-2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-2x!=-5
x!=-5/-2
x!=2+1/2
x∈R
3x/(-2x+5)-x=0
We add all the numbers together, and all the variables
-1x+3x/(-2x+5)=0
We multiply all the terms by the denominator
-1x*(-2x+5)+3x=0
We add all the numbers together, and all the variables
3x-1x*(-2x+5)=0
We multiply parentheses
2x^2+3x-5x=0
We add all the numbers together, and all the variables
2x^2-2x=0
a = 2; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·2·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*2}=\frac{4}{4} =1 $
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