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2(3x-1)=5(2-x)
We move all terms to the left:
2(3x-1)-(5(2-x))=0
We add all the numbers together, and all the variables
2(3x-1)-(5(-1x+2))=0
We multiply parentheses
6x-(5(-1x+2))-2=0
We calculate terms in parentheses: -(5(-1x+2)), so:We get rid of parentheses
5(-1x+2)
We multiply parentheses
-5x+10
Back to the equation:
-(-5x+10)
6x+5x-10-2=0
We add all the numbers together, and all the variables
11x-12=0
We move all terms containing x to the left, all other terms to the right
11x=12
x=12/11
x=1+1/11
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