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-5(-2x-4)5x+5=15
We move all terms to the left:
-5(-2x-4)5x+5-(15)=0
We add all the numbers together, and all the variables
-5(-2x-4)5x-10=0
We multiply parentheses
50x^2+100x-10=0
a = 50; b = 100; c = -10;
Δ = b2-4ac
Δ = 1002-4·50·(-10)
Δ = 12000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12000}=\sqrt{400*30}=\sqrt{400}*\sqrt{30}=20\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{30}}{2*50}=\frac{-100-20\sqrt{30}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{30}}{2*50}=\frac{-100+20\sqrt{30}}{100} $
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