-3z-(12z+3)=3+(8z+8)

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Solution for -3z-(12z+3)=3+(8z+8) equation: 



-3z-(12z+3)=3+(8z+8)

We move all terms to the left:

-3z-(12z+3)-(3+(8z+8))=0

We get rid of parentheses

-3z-12z-(3+(8z+8))-3=0



We calculate terms in parentheses: -(3+(8z+8)), so:

3+(8z+8)

determiningTheFunctionDomain
(8z+8)+3

We get rid of parentheses

8z+8+3

We add all the numbers together, and all the variables

8z+11

Back to the equation:

-(8z+11)



We add all the numbers together, and all the variables

-15z-(8z+11)-3=0

We get rid of parentheses

-15z-8z-11-3=0

We add all the numbers together, and all the variables

-23z-14=0

We move all terms containing z to the left, all other terms to the right

-23z=14

z=14/-23

z=-14/23

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