-4(8-3a)+a=3(12-7a)

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Solution for -4(8-3a)+a=3(12-7a) equation: 



-4(8-3a)+a=3(12-7a)

We move all terms to the left:

-4(8-3a)+a-(3(12-7a))=0

We add all the numbers together, and all the variables

-4(-3a+8)+a-(3(-7a+12))=0

We add all the numbers together, and all the variables

a-4(-3a+8)-(3(-7a+12))=0

We multiply parentheses

a+12a-(3(-7a+12))-32=0



We calculate terms in parentheses: -(3(-7a+12)), so:

3(-7a+12)

We multiply parentheses

-21a+36

Back to the equation:

-(-21a+36)



We add all the numbers together, and all the variables

13a-(-21a+36)-32=0

We get rid of parentheses

13a+21a-36-32=0

We add all the numbers together, and all the variables

34a-68=0

We move all terms containing a to the left, all other terms to the right

34a=68

a=68/34

a=2

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