(3x)(x+10)=(4x+5x)(2x-4)/2

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Solution for (3x)(x+10)=(4x+5x)(2x-4)/2 equation: 



(3x)(x+10)=(4x+5x)(2x-4)/2

We move all terms to the left:

(3x)(x+10)-((4x+5x)(2x-4)/2)=0

We add all the numbers together, and all the variables

3x(x+10)-((+9x)(2x-4)/2)=0

We multiply parentheses

3x^2+30x-((+9x)(2x-4)/2)=0

We multiply parentheses ..

3x^2-((+18x^2-36x)/2)+30x=0

We multiply all the terms by the denominator


3x^2*2)-((+18x^2-36x)+30x*2)=0

Wy multiply elements

6x^3+60x^2=0

We do not support expression: x^3

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