(3v+8)/7=6-(5v-2)/2

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Solution for (3v+8)/7=6-(5v-2)/2 equation: 



(3v+8)/7=6-(5v-2)/2

We move all terms to the left:

(3v+8)/7-(6-(5v-2)/2)=0

We calculate fractions


3v/()+(-(6-(5v-2)*7)/()=0



We calculate terms in parentheses: +(-(6-(5v-2)*7)/(), so:

-(6-(5v-2)*7)/(

We multiply all the terms by the denominator


-(6-(5v-2)*7)



We calculate terms in parentheses: -(6-(5v-2)*7), so:

6-(5v-2)*7

determiningTheFunctionDomain
-(5v-2)*7+6

We multiply parentheses

-35v+14+6

We add all the numbers together, and all the variables

-35v+20

Back to the equation:

-(-35v+20)



We get rid of parentheses

35v-20

Back to the equation:

+(35v-20)



We get rid of parentheses

3v/()+35v-20=0

We multiply all the terms by the denominator


3v+35v*()-20*()=0

We add all the numbers together, and all the variables

3v+35v*()=0

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