-4/5r+2(r-1)+3=3/2r-5

Solution for -4/5r+2(r-1)+3=3/2r-5 equation:

-4/5r+2(r-1)+3=3/2r-5

We move all terms to the left:

-4/5r+2(r-1)+3-(3/2r-5)=0


Domain of the equation: 5r!=0

r!=0/5

r!=0

r∈R



Domain of the equation: 2r-5)!=0

r∈R


We multiply parentheses

-4/5r+2r-(3/2r-5)-2+3=0

We get rid of parentheses

-4/5r+2r-3/2r+5-2+3=0

We calculate fractions


2r+(-8r)/10r^2+(-15r)/10r^2+5-2+3=0

We add all the numbers together, and all the variables

2r+(-8r)/10r^2+(-15r)/10r^2+6=0

We multiply all the terms by the denominator


2r*10r^2+(-8r)+(-15r)+6*10r^2=0

Wy multiply elements

20r^3+60r^2+(-8r)+(-15r)=0

We get rid of parentheses

20r^3+60r^2-8r-15r=0

We do not support erpression: r^3