(3r+12)/9=(2r-4)/2

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Solution for (3r+12)/9=(2r-4)/2 equation: 



(3r+12)/9=(2r-4)/2

We move all terms to the left:

(3r+12)/9-((2r-4)/2)=0

We calculate fractions


3r/()+(-((2r-4)*9)/()=0



We calculate terms in parentheses: +(-((2r-4)*9)/(), so:

-((2r-4)*9)/(

We multiply all the terms by the denominator


-((2r-4)*9)



We calculate terms in parentheses: -((2r-4)*9), so:

(2r-4)*9

We multiply parentheses

18r-36

Back to the equation:

-(18r-36)



We get rid of parentheses

-18r+36

Back to the equation:

+(-18r+36)



We get rid of parentheses

3r/()-18r+36=0

We multiply all the terms by the denominator


3r-18r*()+36*()=0

We add all the numbers together, and all the variables

3r-18r*()=0

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