4(2s+1)=(4s-1)+6

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Solution for 4(2s+1)=(4s-1)+6 equation: 



4(2s+1)=(4s-1)+6

We move all terms to the left:

4(2s+1)-((4s-1)+6)=0

We multiply parentheses

8s-((4s-1)+6)+4=0



We calculate terms in parentheses: -((4s-1)+6), so:

(4s-1)+6

We get rid of parentheses

4s-1+6

We add all the numbers together, and all the variables

4s+5

Back to the equation:

-(4s+5)



We get rid of parentheses

8s-4s-5+4=0

We add all the numbers together, and all the variables

4s-1=0

We move all terms containing s to the left, all other terms to the right

4s=1

s=1/4

s=1/4

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