(3m-5)/(2m+1)=2/6

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Solution for (3m-5)/(2m+1)=2/6 equation:



(3m-5)/(2m+1)=2/6
We move all terms to the left:
(3m-5)/(2m+1)-(2/6)=0
Domain of the equation: (2m+1)!=0
We move all terms containing m to the left, all other terms to the right
2m!=-1
m!=-1/2
m!=-1/2
m∈R
We add all the numbers together, and all the variables
(3m-5)/(2m+1)-(+2/6)=0
We get rid of parentheses
(3m-5)/(2m+1)-2/6=0
We calculate fractions
(18m-30)/(12m+6)+(-4m-2)/(12m+6)=0
We multiply all the terms by the denominator
(18m-30)+(-4m-2)=0
We get rid of parentheses
18m-4m-30-2=0
We add all the numbers together, and all the variables
14m-32=0
We move all terms containing m to the left, all other terms to the right
14m=32
m=32/14
m=2+2/7

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