3x+12=38+4x

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Solution for 3x+12=38+4x equation:



3x+12=38+4x
We move all terms to the left:
3x+12-(38+4x)=0
We add all the numbers together, and all the variables
3x-(4x+38)+12=0
We get rid of parentheses
3x-4x-38+12=0
We add all the numbers together, and all the variables
-1x-26=0
We move all terms containing x to the left, all other terms to the right
-x=26
x=26/-1
x=-26

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