3/2x+4=2x-3

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Solution for 3/2x+4=2x-3 equation:



3/2x+4=2x-3
We move all terms to the left:
3/2x+4-(2x-3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We get rid of parentheses
3/2x-2x+3+4=0
We multiply all the terms by the denominator
-2x*2x+3*2x+4*2x+3=0
Wy multiply elements
-4x^2+6x+8x+3=0
We add all the numbers together, and all the variables
-4x^2+14x+3=0
a = -4; b = 14; c = +3;
Δ = b2-4ac
Δ = 142-4·(-4)·3
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{61}}{2*-4}=\frac{-14-2\sqrt{61}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{61}}{2*-4}=\frac{-14+2\sqrt{61}}{-8} $

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