(3a-12)+(6a-4)=-5

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Solution for (3a-12)+(6a-4)=-5 equation: 



(3a-12)+(6a-4)=-5

We move all terms to the left:

(3a-12)+(6a-4)-(-5)=0

We add all the numbers together, and all the variables

(3a-12)+(6a-4)+5=0

We get rid of parentheses

3a+6a-12-4+5=0

We add all the numbers together, and all the variables

9a-11=0

We move all terms containing a to the left, all other terms to the right

9a=11

a=11/9

a=1+2/9

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