(7x/3)=(1050/2x)

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Solution for (7x/3)=(1050/2x) equation: 



(7x/3)=(1050/2x)

We move all terms to the left:

(7x/3)-((1050/2x))=0



Domain of the equation: 2x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7x/3)-((+1050/2x))=0

We get rid of parentheses

7x/3-((+1050/2x))=0

We calculate fractions


14x^2/6x+()/6x=0

We multiply all the terms by the denominator


14x^2+()=0

We add all the numbers together, and all the variables

14x^2=0

a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{28}=0$

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