-10-2b=(b+2)-6

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Solution for -10-2b=(b+2)-6 equation: 



-10-2b=(b+2)-6

We move all terms to the left:

-10-2b-((b+2)-6)=0



We calculate terms in parentheses: -((b+2)-6), so:

(b+2)-6

We get rid of parentheses

b+2-6

We add all the numbers together, and all the variables

b-4

Back to the equation:

-(b-4)



We get rid of parentheses

-2b-b+4-10=0

We add all the numbers together, and all the variables

-3b-6=0

We move all terms containing b to the left, all other terms to the right

-3b=6

b=6/-3

b=-2

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