(3a+7)-(-3+a)=9(a-1)

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Solution for (3a+7)-(-3+a)=9(a-1) equation: 



(3a+7)-(-3+a)=9(a-1)

We move all terms to the left:

(3a+7)-(-3+a)-(9(a-1))=0

We add all the numbers together, and all the variables

(3a+7)-(a-3)-(9(a-1))=0

We get rid of parentheses

3a-a-(9(a-1))+7+3=0



We calculate terms in parentheses: -(9(a-1)), so:

9(a-1)

We multiply parentheses

9a-9

Back to the equation:

-(9a-9)



We add all the numbers together, and all the variables

2a-(9a-9)+10=0

We get rid of parentheses

2a-9a+9+10=0

We add all the numbers together, and all the variables

-7a+19=0

We move all terms containing a to the left, all other terms to the right

-7a=-19

a=-19/-7

a=2+5/7

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