5(b+1)=2(b+3)

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Solution for 5(b+1)=2(b+3) equation: 



5(b+1)=2(b+3)

We move all terms to the left:

5(b+1)-(2(b+3))=0

We multiply parentheses

5b-(2(b+3))+5=0



We calculate terms in parentheses: -(2(b+3)), so:

2(b+3)

We multiply parentheses

2b+6

Back to the equation:

-(2b+6)



We get rid of parentheses

5b-2b-6+5=0

We add all the numbers together, and all the variables

3b-1=0

We move all terms containing b to the left, all other terms to the right

3b=1

b=1/3

b=1/3

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