5(2x-3)-4(5x-7)=19-2(x+1)

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Solution for 5(2x-3)-4(5x-7)=19-2(x+1) equation: 



5(2x-3)-4(5x-7)=19-2(x+1)

We move all terms to the left:

5(2x-3)-4(5x-7)-(19-2(x+1))=0

We multiply parentheses

10x-20x-(19-2(x+1))-15+28=0



We calculate terms in parentheses: -(19-2(x+1)), so:

19-2(x+1)

determiningTheFunctionDomain
-2(x+1)+19

We multiply parentheses

-2x-2+19

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

-10x-(-2x+17)+13=0

We get rid of parentheses

-10x+2x-17+13=0

We add all the numbers together, and all the variables

-8x-4=0

We move all terms containing x to the left, all other terms to the right

-8x=4

x=4/-8

x=-1/2

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