(35-2x)(20-2x)=594

Solution for (35-2x)(20-2x)=594 equation:

(35-2x)(20-2x)=594

We move all terms to the left:

(35-2x)(20-2x)-(594)=0

We add all the numbers together, and all the variables

(-2x+35)(-2x+20)-594=0

We multiply parentheses ..

(+4x^2-40x-70x+700)-594=0

We get rid of parentheses

4x^2-40x-70x+700-594=0

We add all the numbers together, and all the variables

4x^2-110x+106=0

a = 4; b = -110; c = +106;
Δ = b2-4ac
Δ = -1102-4·4·106
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-102}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+102}{2*4}=\frac{212}{8}
=26+1/2
$