97+3y=2(4y+5)+2(2y+3)

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Solution for 97+3y=2(4y+5)+2(2y+3) equation: 



97+3y=2(4y+5)+2(2y+3)

We move all terms to the left:

97+3y-(2(4y+5)+2(2y+3))=0



We calculate terms in parentheses: -(2(4y+5)+2(2y+3)), so:

2(4y+5)+2(2y+3)

We multiply parentheses

8y+4y+10+6

We add all the numbers together, and all the variables

12y+16

Back to the equation:

-(12y+16)



We get rid of parentheses

3y-12y-16+97=0

We add all the numbers together, and all the variables

-9y+81=0

We move all terms containing y to the left, all other terms to the right

-9y=-81

y=-81/-9

y=+9

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