130+5y=2(4y+7)+2(4y+3)

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Solution for 130+5y=2(4y+7)+2(4y+3) equation: 



130+5y=2(4y+7)+2(4y+3)

We move all terms to the left:

130+5y-(2(4y+7)+2(4y+3))=0



We calculate terms in parentheses: -(2(4y+7)+2(4y+3)), so:

2(4y+7)+2(4y+3)

We multiply parentheses

8y+8y+14+6

We add all the numbers together, and all the variables

16y+20

Back to the equation:

-(16y+20)



We get rid of parentheses

5y-16y-20+130=0

We add all the numbers together, and all the variables

-11y+110=0

We move all terms containing y to the left, all other terms to the right

-11y=-110

y=-110/-11

y=+10

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