(32x+)(72x-24)=0

Solution for (32x+)(72x-24)=0 equation:

(32x+)(72x-24)=0

We add all the numbers together, and all the variables

(+32x)(72x-24)=0

We multiply parentheses ..

(+2304x^2-768x)=0

We get rid of parentheses

2304x^2-768x=0

a = 2304; b = -768; c = 0;
Δ = b2-4ac
Δ = -7682-4·2304·0
Δ = 589824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{589824}=768$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-768)-768}{2*2304}=\frac{0}{4608}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-768)+768}{2*2304}=\frac{1536}{4608}
=1/3
$