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(5x-1)(14x+28)=0
We multiply parentheses ..
(+70x^2+140x-14x-28)=0
We get rid of parentheses
70x^2+140x-14x-28=0
We add all the numbers together, and all the variables
70x^2+126x-28=0
a = 70; b = 126; c = -28;
Δ = b2-4ac
Δ = 1262-4·70·(-28)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23716}=154$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-154}{2*70}=\frac{-280}{140} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+154}{2*70}=\frac{28}{140} =1/5 $
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