y2+2y=29

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Solution for y2+2y=29 equation:



y2+2y=29
We move all terms to the left:
y2+2y-(29)=0
We add all the numbers together, and all the variables
y^2+2y-29=0
a = 1; b = 2; c = -29;
Δ = b2-4ac
Δ = 22-4·1·(-29)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{30}}{2*1}=\frac{-2-2\sqrt{30}}{2} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{30}}{2*1}=\frac{-2+2\sqrt{30}}{2} $

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