4(n-7)-(3-2n)=5

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Solution for 4(n-7)-(3-2n)=5 equation: 



4(n-7)-(3-2n)=5

We move all terms to the left:

4(n-7)-(3-2n)-(5)=0

We add all the numbers together, and all the variables

4(n-7)-(-2n+3)-5=0

We multiply parentheses

4n-(-2n+3)-28-5=0

We get rid of parentheses

4n+2n-3-28-5=0

We add all the numbers together, and all the variables

6n-36=0

We move all terms containing n to the left, all other terms to the right

6n=36

n=36/6

n=6

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