(30/(2x-5))+(27/(2x+1))=13

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Solution for (30/(2x-5))+(27/(2x+1))=13 equation: 



(30/(2x-5))+(27/(2x+1))=13

We move all terms to the left:

(30/(2x-5))+(27/(2x+1))-(13)=0



Domain of the equation: (2x-5))!=0

x∈R





Domain of the equation: (2x+1))!=0

x∈R



We calculate fractions


(60x+30)/((2x-5))*2x+(54x-135)/((2x-5))*2x-13=0

We multiply all the terms by the denominator


(60x+30)+(54x-135)-13*((2x-5))*2x=0

We get rid of parentheses

60x+54x-13*((2x-5))*2x+30-135=0

We add all the numbers together, and all the variables

114x-13*((2x-5))*2x-105=0

We move all terms containing x to the left, all other terms to the right

114x-13*((2x-5))*2x=105

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