2(3x-2)-1=3-2(2x-1)

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Solution for 2(3x-2)-1=3-2(2x-1) equation: 



2(3x-2)-1=3-2(2x-1)

We move all terms to the left:

2(3x-2)-1-(3-2(2x-1))=0

We multiply parentheses

6x-(3-2(2x-1))-4-1=0



We calculate terms in parentheses: -(3-2(2x-1)), so:

3-2(2x-1)

determiningTheFunctionDomain
-2(2x-1)+3

We multiply parentheses

-4x+2+3

We add all the numbers together, and all the variables

-4x+5

Back to the equation:

-(-4x+5)



We add all the numbers together, and all the variables

6x-(-4x+5)-5=0

We get rid of parentheses

6x+4x-5-5=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1

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