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(4x-26)=(3x+19)
We move all terms to the left:
(4x-26)-((3x+19))=0
We get rid of parentheses
4x-((3x+19))-26=0
We calculate terms in parentheses: -((3x+19)), so:We get rid of parentheses
(3x+19)
We get rid of parentheses
3x+19
Back to the equation:
-(3x+19)
4x-3x-19-26=0
We add all the numbers together, and all the variables
x-45=0
We move all terms containing x to the left, all other terms to the right
x=45
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