(3/5)k-(1/10)k=(1/2)k+1

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Solution for (3/5)k-(1/10)k=(1/2)k+1 equation: 



(3/5)k-(1/10)k=(1/2)k+1

We move all terms to the left:

(3/5)k-(1/10)k-((1/2)k+1)=0



Domain of the equation: 5)k!=0

k!=0/1

k!=0

k∈R





Domain of the equation: 10)k!=0

k!=0/1

k!=0

k∈R





Domain of the equation: 2)k+1)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+3/5)k-(+1/10)k-((+1/2)k+1)=0

We multiply parentheses

3k^2-k^2-((+1/2)k+1)=0

We multiply all the terms by the denominator


3k^2*2)k+1)-k^2*2)k+1)-((+1=0

Wy multiply elements

12k^4=0

We do not support ekpression: k^4

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