3/2(4x-1)-(x+3)-6(2x+3)=3/2(x+2)

Solution for 3/2(4x-1)-(x+3)-6(2x+3)=3/2(x+2) equation:

3/2(4x-1)-(x+3)-6(2x+3)=3/2(x+2)

We move all terms to the left:

3/2(4x-1)-(x+3)-6(2x+3)-(3/2(x+2))=0


Domain of the equation: 2(4x-1)!=0

x∈R



Domain of the equation: 2(x+2))!=0

x∈R


We multiply parentheses

3/2(4x-1)-(x+3)-12x-(3/2(x+2))-18=0

We get rid of parentheses

3/2(4x-1)-x-12x-(3/2(x+2))-3-18=0

We calculate fractions


-x-12x+(6xx/(2(4x-1)*2(x+2)))+(-6x4/(2(4x-1)*2(x+2)))-3-18=0


We calculate terms in parentheses: +(6xx/(2(4x-1)*2(x+2))), so:

6xx/(2(4x-1)*2(x+2))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-6x4/(2(4x-1)*2(x+2))), so:

-6x4/(2(4x-1)*2(x+2))

We multiply all the terms by the denominator


-6x4

We add all the numbers together, and all the variables

-6x^4

We do not support expression: x^4