-3b(b-4)=-2b

Solution for -3b(b-4)=-2b equation:

-3b(b-4)=-2b

We move all terms to the left:

-3b(b-4)-(-2b)=0

We multiply parentheses

-3b^2+12b-(-2b)=0

We get rid of parentheses

-3b^2+12b+2b=0

We add all the numbers together, and all the variables

-3b^2+14b=0

a = -3; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-3)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-3}=\frac{-28}{-6}
=4+2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-3}=\frac{0}{-6}
=0
$