(3/4x-2)+(2/5x)+90=180

Solution for (3/4x-2)+(2/5x)+90=180 equation:

(3/4x-2)+(2/5x)+90=180

We move all terms to the left:

(3/4x-2)+(2/5x)+90-(180)=0


Domain of the equation: 4x-2)!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(3/4x-2)+(+2/5x)+90-180=0

We add all the numbers together, and all the variables

(3/4x-2)+(+2/5x)-90=0

We get rid of parentheses

3/4x+2/5x-2-90=0

We calculate fractions


15x/20x^2+8x/20x^2-2-90=0

We add all the numbers together, and all the variables

15x/20x^2+8x/20x^2-92=0

We multiply all the terms by the denominator


15x+8x-92*20x^2=0

We add all the numbers together, and all the variables

23x-92*20x^2=0

Wy multiply elements

-1840x^2+23x=0

a = -1840; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-1840)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-1840}=\frac{-46}{-3680}
=1/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-1840}=\frac{0}{-3680}
=0
$