If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15x^2+45x=0
a = 15; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·15·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*15}=\frac{-90}{30} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*15}=\frac{0}{30} =0 $
| 2（a＋7）-7=9 | | X+0.08x=110.16 | | (2/5x+90)+(3x-2)=180 | | 11x2-121x=0 | | 8x–3=x+17 | | 6x-9=5x+25 | | 3=c+7-17 | | (3x)^2+19x+16=0 | | (x+1)2=(x+2)2-2(x+1) | | 4x^-200=52 | | 4x-2(x+3=5(x-3) | | 1/2(-6k+20)=6+13k | | (4x)^2-36=0 | | (x+5/2)=15 | | 6y=9/33 | | 24-15x=9 | | 7x^-200=52 | | -4x/3=3x+5/4 | | 22z+5z2=15 | | πr^2-πr^2÷2^2=3π | | 5x^-40=5 | | -3+-7x=18 | | -38+8x=-3x-3(1-6x) | | 8x^2-64x+256=0 | | 2y/2=10 | | 4(4x-5)-8x=12 | | 3x^2-20+1=0 | | 12=-8-4x | | x-(x*0.14)=1000000 | | -2+x/7=3 | | x-(x*0.14)=10000 | | 7^-4x=15 |