(3/4)y+2y=(1/2+4)y-3

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Solution for (3/4)y+2y=(1/2+4)y-3 equation: 



(3/4)y+2y=(1/2+4)y-3

We move all terms to the left:

(3/4)y+2y-((1/2+4)y-3)=0



Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 2+4)y-3)!=0

We move all terms containing y to the left, all other terms to the right

4)y-3)!=-2

y!=-2/1

y!=-2

y∈R



We add all the numbers together, and all the variables

(+3/4)y+2y-((1/2+4)y-3)=0

We add all the numbers together, and all the variables

2y+(+3/4)y-((1/2+4)y-3)=0

We multiply parentheses

3y^2+2y-((1/2+4)y-3)=0

We multiply all the terms by the denominator


3y^2*2+4)y-3)+2y*2+4)y-3)-((1=0

Wy multiply elements

6y^2+4)y-3)+2y*2+4)y-3)-((1=0

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