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5x^2+2x-8=16
We move all terms to the left:
5x^2+2x-8-(16)=0
We add all the numbers together, and all the variables
5x^2+2x-24=0
a = 5; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·5·(-24)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*5}=\frac{-24}{10} =-2+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*5}=\frac{20}{10} =2 $
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